A 12k
resistor
has a p.d. of 24mV applied across its terminals. The current through the
resistor will be
AThe answer is :- 4
I = 
= 24 x 10-3
12 x 103
= 2 x 10-3
103
= 2 x 10-3 x 10-3
= 2 x 10-6 A
= 2
A
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